qpym2.hists#
Module Contents#
Functions#
Return the projection of a 2D histogram along the specified axis |
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Return the sum histogram from the components and their norms |
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Return the nbins and range parameters for histogram according to the model |
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Return an empty histogram according to hm |
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create a 1D histogram of esum (m2sum) |
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create a 1D histogram of ediss (v*sqrt(2)) |
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create a 1D histogram of e2 |
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create a 2D histogram of e1 vs e2 |
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create 2D histogram of ediff vs esum (scaled u,v) |
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create 2D histogram of e2 vs esum |
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create 2D histogram of u vs v |
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Return a histogram according to hm. Assumes ‘u’ and ‘v’ branches are present in rdf. |
Data#
API#
- qpym2.hists.HistType = None#
- qpym2.hists.get_h2proj(h2, axis=0)#
Return the projection of a 2D histogram along the specified axis
- h2numpy.ndarray
The 2D histogram.
- axisint
The axis along which to project. Default is 0 (x-axis).
- h1numpy.ndarray
The 1D histogram.
- qpym2.hists.get_sum_hist(comps, norms)#
Return the sum histogram from the components and their norms
- compspandas.DataFrame
The components table.
- normslist
The list of norms.
- sum_histnumpy.ndarray
The sum histogram.
- qpym2.hists.get_hist_settings(hm)#
Return the nbins and range parameters for histogram according to the model
- Args:
hm (hist_model): hist model
- Raises:
TypeError: if the hist_type is not supported
- Returns:
nbins, range: numbr of bins per axis and range (min, max) per axis
TODO: clean w/ copilot
- qpym2.hists.get_empty_hist(hm, return_numpy=True)#
Return an empty histogram according to hm
TODO: clean with copilot
- qpym2.hists.smooth_nph2(h2, smooth=(1, 'k5b'))#
- qpym2.hists.create_hist_m2sum(rdf, hm, rtype='numpy')#
create a 1D histogram of esum (m2sum)
- qpym2.hists.create_hist_m2diff(rdf, hm, rtype='numpy')#
create a 1D histogram of ediss (v*sqrt(2))
- qpym2.hists.create_hist_m2e2(rdf, hm, rtype='numpy')#
create a 1D histogram of e2
- qpym2.hists.create_hist_h2ee(rdf, hm, rtype='numpy')#
create a 2D histogram of e1 vs e2
- qpym2.hists.create_hist_h2esumediff(rdf, hm, rtype='numpy')#
create 2D histogram of ediff vs esum (scaled u,v)
- qpym2.hists.create_hist_h2esume2(rdf, hm, rtype='numpy')#
create 2D histogram of e2 vs esum
- qpym2.hists.create_hist_h2uv(rdf, hm, rtype='numpy')#
create 2D histogram of u vs v
- qpym2.hists.get_hist_from_rdf(rdf, hm, rtype='numpy')#
Return a histogram according to hm. Assumes ‘u’ and ‘v’ branches are present in rdf.
- Args:
rdf (RDataFrame): RDataFrame object hm (hist_model): hist model rtype (str): return type. ‘numpy’ or ‘root’. Default is ‘numpy’.
- Returns:
histogram: (histo, xedges, yedges) if return_numpy is True. otherwise return a THist variant (ROOT)
TODO: there must be a better version than if-else with enum